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假設A=B A^2=AB A^2 -B^2= AB -B^2 (A -B) (A+B)=B(A -B) A+B=B 2B=B 1+1=1????????
最佳解答:
你在一開始的假始已出了問題 假設A=B A^2=AB A^2 -B^2= AB -B^2 (A -B) (A+B)=B(A -B) <-------------- 這裏 因為(A -B) = 0 所以是不可以相除的 A+B=B 2B=B 就我的知識層面 在數學界 暫時未有一個定義是給予 0 over 0 的
其他解答:
the process from third process to fourth process is wrong. because if you both side diveded by A-B, it means that diveded by 0, it is wrong.
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怎樣證實這題1+1=2係錯?發問:
假設A=B A^2=AB A^2 -B^2= AB -B^2 (A -B) (A+B)=B(A -B) A+B=B 2B=B 1+1=1????????
最佳解答:
你在一開始的假始已出了問題 假設A=B A^2=AB A^2 -B^2= AB -B^2 (A -B) (A+B)=B(A -B) <-------------- 這裏 因為(A -B) = 0 所以是不可以相除的 A+B=B 2B=B 就我的知識層面 在數學界 暫時未有一個定義是給予 0 over 0 的
其他解答:
the process from third process to fourth process is wrong. because if you both side diveded by A-B, it means that diveded by 0, it is wrong.
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